Python批量删除只保留最近几天table的代码实例

python/' target='_blank'>python批量删除table,只保留最近几天的table

代码如下：

#!/usr/bin/Python3"""批量删除table,只保留最近几天的table"""import pymysql/' target='_blank'>mysqlimport redef conn_(host='',usr='',passwd='',db='',port=3306,):  conn = pyMySQL.connect(host, usr, passwd, db, port,charset='utf8')  return conndef del_table(conn_,table_pre='',table_suff='%Y%m%d',keep_count=3):  date_form = None  if table_suff == "%Y%m%d":    date_form = "_(\d{4}\d{1,2}\d{1,2})$"    date_len = 8  elif table_suff == "%Y-%m-%d":    date_form = "_(\d{4}-\d{1,2}-\d{1,2})$"    date_len = 10  elif table_suff == "%Y%m":    date_form = "_(\d{4}\d{1,2})$"    date_len = 6  elif table_suff == "%Y-%m":    date_form = "_(\d{4}-\d{1,2})$"    date_len = 7  else:    raise Exception("暂时不支持其他类型的时间后缀")  curs = conn_.cursor()  curs.execute('SHOW TABLES')  data = curs.fetchall()  table_ = r'%s'%table_pre+date_form  list_table = []  i = 0  for table in data:    mt = re.search(table_, table[0])    if mt:      if len(mt.groups()[0]) == date_len:        list_table.append((table[0], mt.groups()[0]))        i += 1  sorted(list_table, key=lambda date: date[1]) #按照表结构后缀时间升序排序  for j in range(i-keep_count):    sql = 'DROP TABLE if exists %s'%list_table[j][0]    curs.execute(sql)  curs.close()  conn_.close()if __name__ == '__main__':  table_pre = "tree_product"  table_suff = "%Y%m%d"  # table_suff = "%Y-%m-%d"  # table_suff = "%Y%m"  # table_suff = "%Y-%m"  conn=conn_('10.0.0.11','root','sctele@root','sxf',port=3306)  del_table(conn,table_pre=table_pre,table_suff=table_suff,keep_count=1)

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