python3 flask实现文件上传功能
时间:2022-01-11 10:31 作者:admin
本文实例为大家分享了python/' target='_blank'>python3-flask文件上传操作的具体代码，供大家参考，具体内容如下
# -*- coding: utf-8 -*-import osimport uuidimport platformfrom flask import Flask,request,redirect,url_forfrom werkzeug.utils import secure_filenameif platform.system() == "Windows": slash = '\\'else: platform.system()=="Linux" slash = '/'UPLOAD_FOLDER = 'upload'ALLOW_EXTENSIONS = set(['html', 'htm', 'doc', 'docx', 'mht', 'pdf'])app = Flask(__name__)app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER#判断文件夹是否存在，如果不存在则创建if not os.path.exists(UPLOAD_FOLDER): os.makedirs(UPLOAD_FOLDER)else: pass# 判断文件后缀是否在列表中def allowed_file(filename): return '.' in filename and \ filename.rsplit('.', 1)[1] in ALLOW_EXTENSIONS@app.route('/',methods=['GET','POST'])def upload_file(): if request.method =='POST': #获取post过来的文件名称，从name=file参数中获取 file = request.files['file'] if file and allowed_file(file.filename): # secure_filename方法会去掉文件名中的中文 filename = secure_filename(file.filename) #因为上次的文件可能有重名，因此使用uuid保存文件 file_name = str(uuid.uuid4()) + '.' + filename.rsplit('.', 1)[1] file.save(os.path.join(app.config['UPLOAD_FOLDER'],file_name)) base_path = os.getcwd() file_path = base_path + slash + app.config['UPLOAD_FOLDER'] + slash + file_name print(file_path) return redirect(url_for('upload_file',filename = file_name)) return ''' <!doctype html> <title>Upload new File</title> <h1>Upload new File</h1> <form action="" method=post enctype=multipart/form-data> <p><input type=file name=file> <input type=submit value=Upload> </form> '''if __name__ == "__main__": app.run(host='0.0.0.0',port=5000)以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持脚本之家。
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