Python实现提取谷歌音乐搜索结果的方法

本文实例讲述了python/' target='_blank'>python实现提取谷歌音乐搜索结果的方法。分享给大家供大家参考。具体如下：

Python的简单脚本，用于提取谷歌音乐搜索页面中的歌曲信息，包括歌曲名，作者，专辑名，现在链接等，最多只提取10页结果。

#! /usr/bin/env python#coding=utf-8'''Created on 2011-8-19@author: yaoboyuan'''from urllib import request,parseimport re,sysdef extractSongRawData(text):  '抓取每一首歌的原始数据'  text = re.sub('\n+','',text)  songList = re.findall('\<tbody.*?\</tbody>',text)  nums = len(songList)  print('search ' + str(nums) + ' songs')  return songListdef translate(text):  '去掉text中的无用字符，转换unicode码'  text = re.sub('\<b>','',text)  text = re.sub('\</b>','',text)  #find the &#25104; and translate into chinese  s = re.findall('&#([0-9]+);',text)  if len(s)<=0:    return text  else:    text = ''    for i in range(len(s)):      value = int(s[i],10) #from str'123' to 10 base's int 124      text += chr(value)  #from value to char    return textdef extractSongName(song):  '提取歌曲名字'  td = re.findall('(?:\<td class\="Title).*(?:\</td>)',song)  name = re.findall('.+?\<a.+?>(.*?)\</a>',td[0])  songName = translate(name[0])  return songNamedef extractAuthorName(song):  '提取作者名字'  td = re.findall('(?:\<td class\="Artist).*(?:\</td>)',song)  name = re.findall('.+?\<a.+?>(.*?)\</a>',td[0])  authorName = name[0]  authorName = translate(authorName)  return authorNamedef extrackAlbumName(song):  '提取专辑名字'  td = re.findall('(?:\<td class\="Album).*(?:\</td>)',song)  name = re.findall('.+?\<a.+?>(.*?)\</a>',td[0])  albumName = translate(name[0])  return albumNamedef extractID(song):  '提取歌曲id'  td = re.findall('''\<tbody id\="([a-zA-Z0-9]+)"''',song)  if len(td)>0:    return td[0]  else:    return songdef extractLink(song):  '提取歌曲下载链接'  td = re.findall('''\<td class\="Icon.*?(?=title\="下载").*?onclick\="(.*?)>''',song)  if len(td) == 0:    return 'NULL'  s = str(td[0])  rawLink = re.findall('http.*?(?=\?)',s)  if len(rawLink) == 0:    return s  link = rawLink[0]  link = re.sub('%3D','=',link)  id = extractID(song)  return link + '?id=' + iddef extractPageNums(text):  '提取返回结果的页数，最多要10页'  pageList = re.findall('page_link',text)  return len(pageList)def extractSongInfo(song):  '提取歌曲信息，返回歌曲列表'  songList = []  for i in range(len(song)):    songName = extractSongName(song[i])    authorName = extractAuthorName(song[i])    albumName = extrackAlbumName(song[i])    link = extractLink(song[i])    songItem = [songName,authorName,albumName,link]    songList.append(songItem)    index = ''    if i<9:      index = '0' + str(i+1)    else:      index = str(i + 1)    #print(index + ' ' + songName + ' ' + authorName + ' ' + albumName + ' ' + link)  return songListdef main():  while True:    url = 'http://www.google.cn/music/search?q='    key = input('请输入歌曲名字或关键字:')    key = parse.quote(key) #统一编码成utf-8    url += key    mf = request.urlopen(url)    c = mf.readall()    c = str(c,encoding = 'utf-8')    num = extractPageNums(c)    print(str(num+1) + ' pages found')    song = extractSongRawData(c)    songList = extractSongInfo(song)    #if the result great than 2 pages, then request all pages    if num>0:      for i in range(num):        start = (i+1)*20        next_page = '&cat=song&start=%d'%(start)        #next_page = parse.quote(next_page) #统一编码成utf-8        url += next_page        mf = request.urlopen(url)        c = mf.readall()        c = str(c,encoding = 'utf-8')        song = extractSongRawData(c)        songList += extractSongInfo(song) #find all results    for i in range(len(songList)): #print the result      index = ''      if i<9:        index = '0' + str(i+1)      else:        index = str(i + 1)      print(index + ' ' + str(songList[i]))if __name__ == '__main__':  main()

希望本文所述对大家的Python程序设计有所帮助。