python实现将英文单词表示的数字转换成阿拉伯数字的方法

本文实例讲述了python/' target='_blank'>python实现将英文单词表示的数字转换成阿拉伯数字的方法。分享给大家供大家参考。具体实现方法如下：

import re_known = {  'zero': 0,  'one': 1,  'two': 2,  'three': 3,  'four': 4,  'five': 5,  'six': 6,  'seven': 7,  'eight': 8,  'nine': 9,  'ten': 10,  'eleven': 11,  'twelve': 12,  'thirteen': 13,  'fourteen': 14,  'fifteen': 15,  'sixteen': 16,  'seventeen': 17,  'eighteen': 18,  'nineteen': 19,  'twenty': 20,  'thirty': 30,  'forty': 40,  'fifty': 50,  'sixty': 60,  'seventy': 70,  'eighty': 80,  'ninety': 90  }def spoken_word_to_number(n):  """Assume n is a positive integer".assert _positive_integer_number('nine hundred') == 900assert spoken_word_to_number('one hundred') == 100assert spoken_word_to_number('eleven') == 11assert spoken_word_to_number('twenty two') == 22assert spoken_word_to_number('thirty-two') == 32assert spoken_word_to_number('forty two') == 42assert spoken_word_to_number('two hundred thirty two') == 232assert spoken_word_to_number('two thirty two') == 232assert spoken_word_to_number('nineteen hundred eighty nine') == 1989assert spoken_word_to_number('nineteen eighty nine') == 1989assert spoken_word_to_number('one thousand nine hundred and eighty nine') == 1989assert spoken_word_to_number('nine eighty') == 980assert spoken_word_to_number('nine two') == 92 # wont be able to convert this oneassert spoken_word_to_number('nine thousand nine hundred') == 9900assert spoken_word_to_number('one thousand nine hundred one') == 1901"""  n = n.lower().strip()  if n in _known:    return _known[n]  else:    inputWordArr = re.split('[ -]', n)  assert len(inputWordArr) > 1 #all single words are known  #Check the pathological case where hundred is at the end or thousand is at end  if inputWordArr[-1] == 'hundred':    inputWordArr.append('zero')    inputWordArr.append('zero')  if inputWordArr[-1] == 'thousand':    inputWordArr.append('zero')    inputWordArr.append('zero')    inputWordArr.append('zero')  if inputWordArr[0] == 'hundred':    inputWordArr.insert(0, 'one')  if inputWordArr[0] == 'thousand':    inputWordArr.insert(0, 'one')  inputWordArr = [word for word in inputWordArr if word not in ['and', 'minus', 'negative']]  currentPosition = 'unit'  prevPosition = None  output = 0  for word in reversed(inputWordArr):    if currentPosition == 'unit':      number = _known[word]      output += number      if number > 9:        currentPosition = 'hundred'      else:        currentPosition = 'ten'    elif currentPosition == 'ten':      if word != 'hundred':        number = _known[word]        if number < 10:          output += number*10        else:          output += number      #else: nothing special      currentPosition = 'hundred'    elif currentPosition == 'hundred':      if word not in [ 'hundred', 'thousand']:        number = _known[word]        output += number*100        currentPosition = 'thousand'      elif word == 'thousand':        currentPosition = 'thousand'      else:        currentPosition = 'hundred'    elif currentPosition == 'thousand':      assert word != 'hundred'      if word != 'thousand':        number = _known[word]        output += number*1000    else:      assert "Can't be here" == None  return(output)

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