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python实现DES加密解密方法实例详解


时间:2021-12-08 14:52 作者:admin


本文实例讲述了python/' target='_blank'>python实现DES加密解密方法。分享给大家供大家参考。具体分析如下:

实现功能:加密中文等字符串
密钥与明文可以不等长
这里只贴代码,加密过程可以自己百度,此处Python代码没有优化

1. desstruct.py DES加密中要使用的结构体

ip= (58, 50, 42, 34, 26, 18, 10, 2,  60, 52, 44, 36, 28, 20, 12, 4,  62, 54, 46, 38, 30, 22, 14, 6,  64, 56, 48, 40, 32, 24, 16, 8,  57, 49, 41, 33, 25, 17, 9 , 1,  59, 51, 43, 35, 27, 19, 11, 3,  61, 53, 45, 37, 29, 21, 13, 5,  63, 55, 47, 39, 31, 23, 15, 7)ip_1=(40, 8, 48, 16, 56, 24, 64, 32,  39, 7, 47, 15, 55, 23, 63, 31,  38, 6, 46, 14, 54, 22, 62, 30,  37, 5, 45, 13, 53, 21, 61, 29,  36, 4, 44, 12, 52, 20, 60, 28,  35, 3, 43, 11, 51, 19, 59, 27,  34, 2, 42, 10, 50, 18, 58, 26,  33, 1, 41, 9, 49, 17, 57, 25)e =(32, 1, 2, 3, 4, 5, 4, 5,   6, 7, 8, 9, 8, 9, 10, 11,   12,13, 12, 13, 14, 15, 16, 17,  16,17, 18, 19, 20, 21, 20, 21,  22, 23, 24, 25,24, 25, 26, 27,  28, 29,28, 29, 30, 31, 32, 1)p=(16, 7, 20, 21, 29, 12, 28, 17,  1, 15, 23, 26, 5, 18, 31, 10,   2, 8, 24, 14, 32, 27, 3, 9,  19, 13, 30, 6, 22, 11, 4, 25)s=[ [[14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7],  [0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8],  [4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0],  [15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13]],  [[15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10],  [3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5],  [0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15],  [13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9]],  [[10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8],  [13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1],  [13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7],  [1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12]], [[7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15],  [13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14,9],  [10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4],  [3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14]], [[2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9],  [14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6],  [4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14],  [11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3]], [[12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11],  [10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8],  [9, 14, 15, 5, 2, 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6],  [4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13]], [[4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1],  [13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6],  [1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2],  [6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12]], [[13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7],  [1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2],  [7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8],  [2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11]]]pc1=(57, 49, 41, 33, 25, 17, 9,  1, 58, 50, 42, 34, 26, 18,  10, 2, 59, 51, 43, 35, 27,  19, 11, 3, 60, 52, 44, 36,  63, 55, 47, 39, 31, 33, 15,  7, 62, 54, 46, 38, 30, 22,  14, 6, 61, 53, 45, 37, 29,  21, 13, 5, 28, 20, 12, 4);pc2= (14, 17, 11, 24, 1, 5, 3, 28,  15, 6, 21, 10, 23, 19, 12, 4,   26, 8, 16, 7, 27, 20, 13, 2,   41, 52, 31, 37, 47, 55, 30, 40,   51, 45, 33, 48, 44, 49, 39, 56,   34, 53, 46, 42, 50, 36, 29, 32)d = ( 1, 1, 2, 2, 2, 2, 2, 2, 1, 2, 2, 2, 2, 2, 2, 1)

2. des.py 加密文件

#_*_ coding:utf-8 _*_#!/usr/bin/env python#Filename:des.pyfrom desstruct import *import re__all__=['desencode']class DES(): '''des 加密''' def __init__(self):  pass #加密 def code(self,from_code,key,code_len,key_len):  output=""  trun_len=0  #将密文和密钥转换为二进制  code_string=self._functionCharToA(from_code,code_len)  code_key=self._functionCharToA(key,key_len)  #如果密钥长度不是16的整数倍则以增加0的方式变为16的整数倍  if code_len%16!=0:   real_len=(code_len/16)*16+16  else:   real_len=code_len  if key_len%16!=0:   key_len=(key_len/16)*16+16  key_len*=4  #每个16进制占4位  trun_len=4*real_len  #对每64位进行一次加密  for i in range(0,trun_len,64):   run_code=code_string[i:i+64]   l=i%key_len   run_key=code_key[l:l+64]   #64位明文、密钥初始置换   run_code= self._codefirstchange(run_code)   run_key= self._keyfirstchange(run_key)   #16次迭代   for j in range(16):    #取出明文左右32位    code_r=run_code[32:64]    code_l=run_code[0:32]    #64左右交换    run_code=code_r    #右边32位扩展置换    code_r= self._functionE(code_r)    #获取本轮子密钥    key_l=run_key[0:28]    key_r=run_key[28:56]    key_l=key_l[d[j]:28]+key_l[0:d[j]]    key_r=key_r[d[j]:28]+key_r[0:d[j]]    run_key=key_l+key_r    key_y= self._functionKeySecondChange(run_key)    #异或    code_r= self._codeyihuo(code_r,key_y)    #S盒代替/选择    code_r= self._functionS(code_r)    #P转换    code_r= self._functionP(code_r)    #异或    code_r= self._codeyihuo(code_l,code_r)    run_code+=code_r   #32互换   code_r=run_code[32:64]   code_l=run_code[0:32]   run_code=code_r+code_l   #将二进制转换为16进制、逆初始置换   output+=self._functionCodeChange(run_code)  return output #异或  def _codeyihuo(self,code,key):  code_len=len(key)  return_list=''  for i in range(code_len):   if code[i]==key[i]:    return_list+='0'   else:    return_list+='1'  return return_list #密文或明文初始置换 def _codefirstchange(self,code):  changed_code=''  for i in range(64):   changed_code+=code[ip[i]-1]  return changed_code #密钥初始置换 def _keyfirstchange (self,key):  changed_key=''  for i in range(56):   changed_key+=key[pc1[i]-1]  return changed_key #逆初始置换 def _functionCodeChange(self, code):  lens=len(code)/4  return_list=''  for i in range(lens):   list=''   for j in range(4):    list+=code[ip_1[i*4+j]-1]   return_list+="%x" %int(list,2)  return return_list #扩展置换  def _functionE(self,code):  return_list=''  for i in range(48):   return_list+=code[e[i]-1]  return return_list   #置换P   def _functionP(self,code):  return_list=''  for i in range(32):   return_list+=code[p[i]-1]  return return_list #S盒代替选择置换 def _functionS(self, key):  return_list=''  for i in range(8):   row=int( str(key[i*6])+str(key[i*6+5]),2)   raw=int(str( key[i*6+1])+str(key[i*6+2])+str(key[i*6+3])+str(key[i*6+4]),2)   return_list+=self._functionTos(s[i][row][raw],4)  return return_list #密钥置换选择2 def _functionKeySecondChange(self,key):  return_list=''  for i in range(48):   return_list+=key[pc2[i]-1]  return return_list #将十六进制转换为二进制字符串 def _functionCharToA(self,code,lens):  return_code=''  lens=lens%16  for key in code:   code_ord=int(key,16)   return_code+=self._functionTos(code_ord,4)    if lens!=0:   return_code+='0'*(16-lens)*4  return return_code #二进制转换 def _functionTos(self,o,lens):  return_code=''  for i in range(lens):   return_code=str(o>>i &1)+return_code  return return_code#将unicode字符转换为16进制def tohex(string): return_string='' for i in string:  return_string+="%02x"%ord(i) return return_stringdef tounicode(string): return_string='' string_len=len(string) for i in range(0,string_len,2):  return_string+=chr(int(string[i:i+2],16)) return return_string#入口函数def desencode(from_code,key): #转换为16进制 from_code=tohex(from_code) key=tohex(key) des=DES() key_len=len(key) string_len=len(from_code)   if string_len<1 or key_len<1:  print 'error input'  return False key_code= des.code(from_code,key,string_len,key_len) return key_code#测试if __name__ == '__main__': print desencode('我是12345678刘就是我abcdwfd','0f1571c947刘')#返回密文为: 84148584371a6a1fe99e1da0ce1e34649b88ed15098e8aa4b8eb0bf24885c658

3. 解密文件

#_*_coding:utf-8_*_#!/usr/bin/env python#Filename:des.pyfrom desstruct import *import re__all__=['desdecode']class DES(): '''解密函数,DES加密与解密的方法相差不大  只是在解密的时候所用的子密钥与加密的子密钥相反 ''' def __init__(self):  pass def decode(self,string,key,key_len,string_len):  output=""  trun_len=0  num=0  #将密文转换为二进制  code_string=self._functionCharToA(string,string_len)  #获取字密钥  code_key=self._getkey(key,key_len)  #如果密钥长度不是16的整数倍则以增加0的方式变为16的整数倍  real_len=(key_len/16)+1 if key_len%16!=0 else key_len/16  trun_len=string_len*4  #对每64位进行一次加密  for i in range(0,trun_len,64):   run_code=code_string[i:i+64]   run_key=code_key[num%real_len]   #64位明文初始置换   run_code= self._codefirstchange(run_code)   #16次迭代   for j in range(16):    code_r=run_code[32:64]    code_l=run_code[0:32]    #64左右交换     run_code=code_r    #右边32位扩展置换    code_r= self._functionE(code_r)    #获取本轮子密钥    key_y=run_key[15-j]    #异或    code_r= self._codeyihuo(code_r,key_y)    #S盒代替/选择    code_r= self._functionS(code_r)    #P转换    code_r= self._functionP(code_r)    #异或    code_r= self._codeyihuo(code_l,code_r)    run_code+=code_r   num+=1   #32互换   code_r=run_code[32:64]   code_l=run_code[0:32]   run_code=code_r+code_l   #将二进制转换为16进制、逆初始置换   output+=self._functionCodeChange(run_code)  return output #获取子密钥 def _getkey(self,key,key_len):  #将密钥转换为二进制  code_key=self._functionCharToA(key,key_len)  a=['']*16  real_len=(key_len/16)*16+16 if key_len%16!=0 else key_len  b=['']*(real_len/16)  for i in range(real_len/16):   b[i]=a[:]  num=0  trun_len=4*key_len  for i in range(0,trun_len,64):   run_key=code_key[i:i+64]   run_key= self._keyfirstchange(run_key)   for j in range(16):    key_l=run_key[0:28]    key_r=run_key[28:56]    key_l=key_l[d[j]:28]+key_l[0:d[j]]    key_r=key_r[d[j]:28]+key_r[0:d[j]]    run_key=key_l+key_r    key_y= self._functionKeySecondChange(run_key)    b[num][j]=key_y[:]   num+=1  return b  #异或         def _codeyihuo(self,code,key):  code_len=len(key)  return_list=''  for i in range(code_len):   if code[i]==key[i]:    return_list+='0'   else:    return_list+='1'  return return_list #密文或明文初始置换          def _codefirstchange(self,code):  changed_code=''  for i in range(64):   changed_code+=code[ip[i]-1]  return changed_code #密钥初始置换 def _keyfirstchange (self,key):  changed_key=''  for i in range(56):   changed_key+=key[pc1[i]-1]  return changed_key #逆初始置换 def _functionCodeChange(self, code):  return_list=''  for i in range(16):   list=''   for j in range(4):    list+=code[ip_1[i*4+j]-1]   return_list+="%x" %int(list,2)  return return_list #扩展置换  def _functionE(self,code):  return_list=''  for i in range(48):   return_list+=code[e[i]-1]  return return_list   #置换P  def _functionP(self,code):  return_list=''  for i in range(32):   return_list+=code[p[i]-1]  return return_list #S盒代替选择置换  def _functionS(self, key):  return_list=''  for i in range(8):   row=int( str(key[i*6])+str(key[i*6+5]),2)   raw=int(str( key[i*6+1])+str(key[i*6+2])+str(key[i*6+3])+str(key[i*6+4]),2)   return_list+=self._functionTos(s[i][row][raw],4)  return return_list #密钥置换选择2 def _functionKeySecondChange(self,key):  return_list=''  for i in range(48):   return_list+=key[pc2[i]-1]  return return_list #将十六进制转换为二进制字符串 def _functionCharToA(self,code,lens):  return_code=''  lens=lens%16  for key in code:   code_ord=int(key,16)   return_code+=self._functionTos(code_ord,4)  if lens!=0:   return_code+='0'*(16-lens)*4  return return_code #二进制转换 def _functionTos(self,o,lens):  return_code=''  for i in range(lens):   return_code=str(o>>i &1)+return_code  return return_code#将unicode字符转换为16进制def tohex(string): return_string='' for i in string:  return_string+="%02x"%ord(i) return return_stringdef tounicode(string): return_string='' string_len=len(string) for i in range(0,string_len,2):  return_string+=chr(int(string[i:i+2],16)) return return_string#入口函数def desdecode(from_code,key): key=tohex(key) des=DES() key_len=len(key) string_len=len(from_code) if string_len%16!=0:  return False if string_len<1 or key_len<1:  return False key_code= des.decode(from_code,key,key_len,string_len) return tounicode(key_code)#测试if __name__ == '__main__': print desdecode('84148584371a6a1fe99e1da0ce1e34649b88ed15098e8aa4b8eb0bf24885c658','0f1571c947刘'

解密后为: 我是12345678刘就是我abcdwfd

Python DES 加密解密,就是大家所谓想要的那个非常快速的方法
这个要借助Crypto.Cipher这个插件来实现的,引用后只需要写如下代码即可

from Crypto.Cipher import DESclass MyDESCrypt:    key = chr(11)+chr(11)+chr(11)+chr(11)+chr(11)+chr(11)+chr(11)+chr(11)  iv = chr(22)+chr(22)+chr(22)+chr(22)+chr(22)+chr(22)+chr(22)+chr(22)    def __init__(self,key='',iv=''):    if len(key)> 0:      self.key = key    if len(iv)>0 :      self.iv = iv      def ecrypt(self,ecryptText):    try:      cipherX = DES.new(self.key, DES.MODE_CBC, self.iv)      pad = 8 - len(ecryptText) % 8      padStr = ""      for i in range(pad):       padStr = padStr + chr(pad)      ecryptText = ecryptText + padStr      x = cipherX.encrypt(ecryptText)      return x.encode('hex_codec').upper()    except:      return ""       def decrypt(self,decryptText):    try:            cipherX = DES.new(self.key, DES.MODE_CBC, self.iv)      str = decryptText.decode('hex_codec')      y = cipherX.decrypt(str)      return y[0:ord(y[len(y)-1])*-1]    except:      return ""

建议大家可以结合一些插件使用,更方便与快捷

希望本文所述对大家的Python程序设计有所帮助。

(责任编辑:admin)






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