Python3处理文件中每个词的方法

本文实例讲述了python/' target='_blank'>python3处理文件中每个词的方法。分享给大家供大家参考。具体实现方法如下：

''''' Created on Dec 21, 2012 处理文件中的每个词 @author: liury_lab ''' import codecs the_file = codecs.open('d:/text.txt', 'rU', 'UTF-8') for line in the_file:   for word in line.split():     print(word, end = "|") the_file.close() # 若词的定义有变，可使用正则表达式 # 如词被定义为数字字母，连字符或单引号构成的序列 import re the_file = codecs.open('d:/text.txt', 'rU', 'UTF-8') print() print('************************************************************************') re_word = re.compile('[\w\'-]+') for line in the_file:   for word in re_word.finditer(line):     print(word.group(0), end = "|") the_file.close() # 封装成迭代器 def words_of_file(file_path, line_to_words = str.split):   the_file = codecs.open('d:/text.txt', 'rU', 'UTF-8')   for line in the_file:     for word in line_to_words(line):       yield word   the_file.close() print() print('************************************************************************') for word in words_of_file('d:/text.txt'):   print(word, end = '|') def words_by_re(file_path, repattern = '[\w\'-]+'):   the_file = codecs.open('d:/text.txt', 'rU', 'UTF-8')   re_word = re.compile('[\w\'-]+')    def line_to_words(line):     for mo in re_word.finditer(line):       yield mo.group(0) # 原书为return，发现结果不对，改为yield   return words_of_file(file_path, line_to_words) print() print('************************************************************************') for word in words_by_re('d:/text.txt'):   print(word, end = '|')

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