Python新手实现2048小游戏

接触 python/' target='_blank'>python 不久，看到很多人写2048，自己也捣鼓了一个，主要是熟悉Python语法。

程序使用Python3 写的，代码150行左右，基于控制台，方向键使用输入字符模拟。

演示图片

2048.py

# -*- coding:UTF-8 -*-#! /usr/bin/python3 import random v = [[0, 0, 0, 0],   [0, 0, 0, 0],   [0, 0, 0, 0],   [0, 0, 0, 0]] def display(v, score):    '''显示界面     '''    print('{0:4} {1:4} {2:4} {3:4}'.format(v[0][0], v[0][1], v[0][2], v[0][3]))    print('{0:4} {1:4} {2:4} {3:4}'.format(v[1][0], v[1][1], v[1][2], v[1][3]))    print('{0:4} {1:4} {2:4} {3:4}'.format(v[2][0], v[2][1], v[2][2], v[2][3]))    print('{0:4} {1:4} {2:4} {3:4}'.format(v[3][0], v[3][1], v[3][2], v[3][3]), '  Total score: ', score) def init(v):    '''随机分布网格值         '''    for i in range(4):        v[i] = [random.choice([0, 0, 0, 2, 2, 4]) for x in range(4)] def align(vList, direction):    '''对齐非零的数字     direction == 'left'：向左对齐，例如[8,0,0,2]左对齐后[8,2,0,0]    direction == 'right'：向右对齐，例如[8,0,0,2]右对齐后[0,0,8,2]    '''     # 移除列表中的0    for i in range(vList.count(0)):        vList.remove(0)    # 被移除的0    zeros = [0 for x in range(4 - len(vList))]    # 在非0数字的一侧补充0    if direction == 'left':        vList.extend(zeros)    else:        vList[:0] = zeros     def addSame(vList, direction):    '''在列表查找相同且相邻的数字相加, 找到符合条件的返回True，否则返回False,同时还返回增加的分数         direction == 'left':从右向左查找，找到相同且相邻的两个数字，左侧数字翻倍，右侧数字置0    direction == 'right':从左向右查找，找到相同且相邻的两个数字，右侧数字翻倍，左侧数字置0    '''    score = 0    if direction == 'left':        for i in [0, 1, 2]:            if vList[i] == vList[i+1] != 0:                 vList[i] *= 2                vList[i+1] = 0                score += vList[i]                return {'bool':True, 'score':score}    else:        for i in [3, 2, 1]:            if vList[i] == vList[i-1] != 0:                vList[i-1] *= 2                vList[i] = 0                score += vList[i-1]                return {'bool':True, 'score':score}    return {'bool':False, 'score':score} def handle(vList, direction):    '''处理一行（列）中的数据，得到最终的该行（列）的数字状态值, 返回得分     vList: 列表结构，存储了一行（列）中的数据    direction: 移动方向,向上和向左都使用方向'left'，向右和向下都使用'right'    '''    totalScore = 0    align(vList, direction)    result = addSame(vList, direction)    while result['bool'] == True:        totalScore += result['score']        align(vList, direction)        result = addSame(vList, direction)    return totalScore      def operation(v):    '''根据移动方向重新计算矩阵状态值，并记录得分    '''    totalScore = 0    gameOver = False    direction = 'left'    op = input('operator:')    if op in ['a', 'A']:  # 向左移动        direction = 'left'        for row in range(4):            totalScore += handle(v[row], direction)    elif op in ['d', 'D']: # 向右移动        direction = 'right'        for row in range(4):            totalScore += handle(v[row], direction)    elif op in ['w', 'W']: # 向上移动        direction = 'left'        for col in range(4):            # 将矩阵中一列复制到一个列表中然后处理            vList = [v[row][col] for row in range(4)]            totalScore += handle(vList, direction)            # 从处理后的列表中的数字覆盖原来矩阵中的值            for row in range(4):                v[row][col] = vList[row]    elif op in ['s', 'S']: # 向下移动        direction = 'right'        for col in range(4):            # 同上            vList = [v[row][col] for row in range(4)]            totalScore += handle(vList, direction)            for row in range(4):                v[row][col] = vList[row]    else:        print('Invalid input, please enter a charactor in [W, S, A, D] or the lower')        return {'gameOver':gameOver, 'score':totalScore}     # 统计空白区域数目 N    N = 0    for q in v:      N += q.count(0)    # 不存在剩余的空白区域时，游戏结束    if N == 0:        gameOver = True        return {'gameOver':gameOver, 'score':totalScore}     # 按2和4出现的几率为3/1来产生随机数2和4    num = random.choice([2, 2, 2, 4])     # 产生随机数k，上一步产生的2或4将被填到第k个空白区域    k = random.randrange(1, N+1)    n = 0    for i in range(4):        for j in range(4):            if v[i][j] == 0:                n += 1                if n == k:                    v[i][j] = num                    break     return {'gameOver':gameOver, 'score':totalScore} init(v)score = 0print('Input：W(Up) S(Down) A(Left) D(Right), press <CR>.')while True:    display(v, score)    result = operation(v)    if result['gameOver'] == True:        print('Game Over, You failed!')        print('Your total score:', score)    else:        score += result['score']        if score >= 2048:            print('Game Over, You Win!!!')            print('Your total score:', score)

以上所述就是本文给大家分享的全部代码了，希望能够对大家学习Python有所帮助。