Python实现读取目录所有文件的文件名并保存到txt文件代码
时间:2021-11-09 10:26 作者:admin610456
代码: (使用os.listdir)
复制代码 代码如下:
import os
def ListFilesToTxt(dir,file,wildcard,recursion):
exts = wildcard.split(" ")
files = os.listdir(dir)
for name in files:
fullname=os.path.join(dir,name)
if(os.path.isdir(fullname) & recursion):
ListFilesToTxt(fullname,file,wildcard,recursion)
else:
for ext in exts:
if(name.endswith(ext)):
file.write(name + "\n")
break
def Test():
dir="J:\\1"
outfile="binaries.txt"
wildcard = ".txt .exe .dll .lib"
file = open(outfile,"w")
if not file:
print ("cannot open the file %s for writing" % outfile)
ListFilesToTxt(dir,file,wildcard, 1)
file.close()
Test()
代码:(使用os.walk) walk递归地对目录及子目录处理,每次返回的三项分别为:当前递归的目录,当前递归的目录下的所有子目录,当前递归的目录下的所有文件。
复制代码 代码如下:
import os
def ListFilesToTxt(dir,file,wildcard,recursion):
exts = wildcard.split(" ")
for root, subdirs, files in os.walk(dir):
for name in files:
for ext in exts:
if(name.endswith(ext)):
file.write(name + "\n")
break
if(not recursion):
break
def Test():
dir="J:\\1"
outfile="binaries.txt"
wildcard = ".txt .exe .dll .lib"
file = open(outfile,"w")
if not file:
print ("cannot open the file %s for writing" % outfile)
ListFilesToTxt(dir,file,wildcard, 0)
file.close()
Test()
(责任编辑:admin)