python实现猜数字游戏(无重复数字)示例分享

复制代码 代码如下:
import time, random

class GuessNum:
def __init__(self):
self._num = ''
self.input_num = []
self.count = 1 #猜对所用次数
self.sec = 0 #猜对所用时间
self._generate_num()

def _generate_num(self): #产生不重复的四个数字
seq_zton = list(range(10))
for i in range(0, 4):
a = str(random.choice(seq_zton)) #选出一个数字
self._num += a
seq_zton.remove(int(a)) #注意a的类型

self.sec = time.clock() #开始计时

def check_answer(self):
return self._num

def check_input(self):
num_pos, num_value = 0, 0 #位置对和数值对的分别的个数
tmp = input("Please input the number you guess(No repetition),or 'c' to check the answer:")
if tmp == 'c':
print(self.check_answer())
tof = self.check_input()
return tof
elif not tmp.isalnum or not len(tmp) == 4:
print("Wrong format!")
tof = self.check_input() #需要优化
return tof
self.input_num = list(tmp)
lst_temp = list(self._num)
if self.input_num == lst_temp: #猜对
self.prt_vic()
return True
for i in lst_temp:
if i in self.input_num:
if lst_temp.index(i) == self.input_num.index(i): #位置也相同
num_pos += 1
num_value += 1
else:
num_value += 1

self.prt_state(num_pos, num_value)
self.count += 1
return False

def prt_state(self, num_pos, num_value):
print("You've got %d numbers with the right position and %d numbers with the right value only" % (num_pos, num_value))

def prt_vic(self):
t = time.clock()
self.sec = t - self.sec
print("Congratulations!You have successfully got the right number!")
print("%d times and %.2f sec in total to get the right answer" % (self.count, self.sec))

gn = GuessNum()
while True:
ss = gn.check_input()
if ss:
b = input("Continue? y/n:")
if b == 'n':
break
else:
gn = GuessNum()
continue