SQL中实现SPLIT函数几种方法总结(必看篇)

例1

代码如下

create function f_split(@SourceSql varchar(8000),@StrSeprate varchar(10))returns @temp table(a varchar(100))--实现split功能 的函数--date :2003-10-14as begindeclare @i intset @SourceSql=rtrim(ltrim(@SourceSql))set @i=charindex(@StrSeprate,@SourceSql)while @i>=1begininsert @temp values(left(@SourceSql,@i-1))set @SourceSql=substring(@SourceSql,@i+1,len(@SourceSql)-@i)set @i=charindex(@StrSeprate,@SourceSql)endif @SourceSql<>'' insert @temp values(@SourceSql)return endselect * from dbo.f_split('1,2,3,4',',')a -------------------- 1234（所影响的行数为 4 行）

例2

代码如下

--SQL Server Split函数--Author:zc_0101 --说明：--支持分割符多字节--使用方法 --Select * FROM DBO.F_SQLSERVER_SPLIT('1203401230105045','0') --select * from DBO.F_SQLSERVER_SPLIT('abc1234a12348991234','1234') --Select * from DBO.F_SQLSERVER_SPLIT('ABC',',') CREATE FUNCTION F_SQLSERVER_SPLIT(@Long_str varchar(8000),@split_str varchar(100)) RETURNS @tmp TABLE( ID inT IDENTITY PRIMARY KEY, short_str varchar(8000) ) AS BEGIN DECLARE @long_str_Tmp varchar(8000),@short_str varchar(8000),@split_str_length int SET @split_str_length = LEN(@split_str) IF CHARINDEX(@split_str,@Long_str)=1 SET @long_str_Tmp=SUBSTRING(@Long_str,@split_str_length+1,LEN(@Long_str)-@split_str_length)ELSESET @long_str_Tmp=@Long_strIF CHARINDEX(REVERSE(@split_str),REVERSE(@long_str_Tmp))>1 SET @long_str_Tmp=@long_str_Tmp+@split_str ELSE SET @long_str_Tmp=@long_str_Tmp IF CHARINDEX(@split_str,@long_str_Tmp)=0Insert INTO @tmp select @long_str_Tmp ELSEBEGINWHILE CHARINDEX(@spl(www.jb51.net)it_str,@long_str_Tmp)>0 BEGIN SET @short_str=SUBSTRING(@long_str_Tmp,1,CHARINDEX(@split_str,@long_str_Tmp)-1) DECLARE @long_str_Tmp_LEN INT,@split_str_Position_END int SET @long_str_Tmp_LEN = LEN(@long_str_Tmp) SET @split_str_Position_END = LEN(@short_str)+@split_str_length SET @long_str_Tmp=REVERSE(SUBSTRING(REVERSE(@long_str_Tmp),1,@long_str_Tmp_LEN-@split_str_Position_END))IF @short_str<>'' Insert INTO @tmp select @short_str END ENDRETURN END

例3

Sql2000andSql2005实用的Split函数

代码如下

sql2000 CREATE FUNCTION [dbo].[splitstring_array] ( @string nvarchar(4000),@split char(1) ) RETURNS @array table( oneStr nvarchar(100) ) ASBEGINdeclare @v_code varchar(60) --zell 2006-05-26 --set @string = replace(@string,' ',@split) --set @string = replace(@string,'，',@split) while len(@string) > 0 beginif charindex(@split,@string,1) != 0 beginset @v_code = substring(@string,1,charindex(@split,@string,1)-1) set @string = substring(@string,charindex(@split,@string,1)+1,len(@string)) endelse if charindex(@split,@string,1) = 0 beginset @v_code = @string set @string = ''endinsert into @array(onestr) values(@v_code) endRETURNENDsql2005 CREATE function [dbo].[func_splitid] (@str varchar(max),@split varchar(10)) RETURNS @t Table (c1 nvarchar(100)) ASBEGINDECLARE @x XML SET @x = CONVERT(XML,'<items><item id="' + REPLACE(@str, @split, '"/><item id="') + '"/></items>') INSERT INTO @t SELECT x.item.value('@id[1]', 'nvarchar(100)') FROM @x.nodes('//items/item') AS x(item) RETURN END 

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